Question

Please answer this question

This question is from Class 11 - Mathematics.

Answer 1

Answer:

18 players received in exactly two sports

Step-by-step explanation:

by formula

let F=football ; B=basketball ; C=Cricket

then according to question

n(F)=38 ; n(B)=15 ; n(C)=20

n(F∪B∪C)=58

n(F∩B∩C)=3

to find: n(F∩B)+n(B∩C)+n(F∩C)

n(F∪B∪C)=n(F)+n(B)+n(C)-n(F∩B)-n(B∩C)-n(F∩C)+n(F∩B∩C)

58=38+15+20+3-n(F∩B)-n(B∩C)-n(F∩C)

58=76-n(F∩B)-n(B∩C)-n(F∩C)

n(F∩B)+n(B∩C)+n(F∩C)=76-58

n(F∩B)+n(B∩C)+n(F∩C)=18

So, 18 players received in exactly two sports

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