Question

please answer this question.. unjent...​

Answer 1

cotA=(4/3)

tanA=(3/4)

sinA=3/5,

cosA=4/5

now

$\frac{1 - ( {tana)}^{2} }{1 + ( { tana) }^{2} } =$

$\frac{1 - \frac{9}{16} }{1 + \frac{9}{16} } = \frac{16 - 9}{16 + 9} = \frac{7}{25}$

And

$(cosa ) ^{2} - ( sina) ^{2}$

$= \frac{16}{25} - \frac{9}{25}$

$= \frac{7}{25}$

so given statement is correct