Math, asked by jiyarajput94, 5 months ago

please answer this question urgently

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Answered by mahadevidndm

0

Step-by-step explanation:

D^s ............. . . . . .

Answered by Anonymous

1

$\large{\huge{\underline \mathbb{ \overline { \mid{ \blue{Answer} \mid}}}} }$

$\large \sf {D}^{m} {D}^{n} = \underline {D}^{n + m}$

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