Question

please answer this question urgently


position of a particle is given by x=At^2 + Be^ alpha x t. The particle is at x=-1m at t=0 moving with a speed v=2m/s. The value of A so that its initial acceleration is zero will be
wrong answer will be reported ​

Answer 1

Ok.

dx^2/dt^2 = acceleration

This question I guess is incomplete. There should be information about the initial motion of body also.

Answer 2

Answer:

The particle is at x=-1m at t=0 moving with a speed v=2m/s. The value of A so that its initial acceleration is zero will be 1.1.