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Hi ,
Draw a rough diagram of given data
|A
|
|
| 60
|__________|___________45_
B. C. D
Join A to C and D
Let
Height of the aeroplane from the
ground = AB = 200m
Width of the river = CD
i) In right triangle ABD,
tan 45° = AB / BD
1 = 200 / BD
BD = 200m ---( 1 )
ii ) In triangle ABC ,
Tan 60° = AB / BC
√3 = 200 / BC
BC = 200 /√3
BC =( 200 √3)/( √3 × √3 )
BC = 200√3 / 3----( 2 )
iii ) width of the river =
CD = BD - BC
= 200 - 200√3/3
= 200( 1 - √3 /3)
= 200( 3 - √3 )/3
=( 200/3) ( 3 - √3 ) m
I hope this helps you.
Navaneeth999:
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