Math, asked by sss57, 1 year ago

please answer this question with a solution

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Answered by rzr531
1
let x,y be the number of food F1 and F2 respectively such that x,y >0
the required diet is 40 of V1 and 50 of V2
so the constraints become
2x+4y>=40
3x+2y>=50
and the total cost to be minimised is
3x+2.5y
hope this helps
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