Question

please answer this question with proper
explanation​

Answer 1

douled because all a re doubled

Answer 2

Hi there...

:)

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the units of power will obviously be unaffected...

picture it this way...

mass   = M       time = T

length = L        

then power[P]= Work[W]/time[T]

⇒[P] = forcexdisplacementx$T^{-1}$

⇒[P] = ML$T^{-2}$xLx$T^{-1}$

Dimensions(i.e;units of power)  

[P] = ML²$T^{-3}$

and if in any way u either double the units, quadraple the units of mass length whatever... the units of power will remain unaffected but only its magnitude will change...

it will be constant (k) times the units again

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Cheers;)