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>>> In the given figure, segment AX and BY are equal and AX∣∣BY
The line segment AX∣∣BY and line segment AB join the parallel line at A and B.
And line segment XY cut line AB at point P
Then, in ΔAXP and ΔPYB
AX=BY ....... (Given)
∠XAP(3)=∠YBP(4) (Adjacent angle )
∠AXP(1)=∠PYB(2) (Adjacent angle )
Then ΔAPX≅ΔBPY
(B) The ΔAPX≅ΔBPY
Then AP=BP and XP=PY
˙·٠•●♥ THUS, THE LINE SEGMENT AB AND XY BISECT EACH OTHER. ♥●•٠·˙
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tum kya bolrahe Sakshi........
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