Math, asked by amishafilomeena1003, 8 months ago

please answer this question with showing all the workings if you know the answer then only answer else reported answer correctly​

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Answers

Answered by Anonymous
12

ANSWER✔

\large\underline\bold{GIVEN,}

\sf\dashrightarrow \angle FEG= 90\degree

\sf\dashrightarrow \angle GAB = \angle 1

\sf\dashrightarrow \angle HBC =40\degree

\sf\dashrightarrow \angle ICD= x\degree

\sf\dashrightarrow \angle JDE= 60\degree

\sf\dashrightarrow \angle  EAB = 90\degree

\large\underline\bold{TO\:FIND,}

\sf\dashrightarrow\text{ the value of angle 1 and x}

✯.PROPERTY IN USE,

\bf{\boxed{\bf{ \star\:\: SUM\:OF\:EXTERIOR\:ANGLES\:OF\: QUADRILATERAL=360\degree\:\: \star}}}

\large\underline\bold{SOLUTION,}

\sf\dashrightarrow \text{ first finding the value of angle 1,}

\sf\therefore\text{ by angle sum property,}

\sf\dashrightarrow \angle GAB +\angle EAB=180\degree

\sf\implies \angle 1+ 90\degree=180\degree

\sf\implies \angle 1 =180-90

\sf\implies \angle 1= 90\degree

\large{\boxed{\bf{ \star\:\:\angle 1= 90\degree \:\: \star}}}

\sf\star \:\: \text{ Now, finding the value of x,}

\sf\therefore SUM\:OF\:EXTERIOR\:ANGLES\:OF\: QUADRILATERAL=360\degree

\sf\dashrightarrow \angle FEG+ \angle GAB + \angle HBC + \angle ICD+ \angle JDE=360\degree

\sf\implies 90\degree + 90\degree + 40\degree +x +60\degree=360\degree

\sf\implies 180\degree+100\degree = 360\degree

\sf\implies 280\degree+ x=360\degree

\sf\implies  x=360-280

\sf\implies x= 80\degree

\large{\boxed{\bf{ \star\:x= 80\degree \:\: \star}}}

\large\underline\bold{THE\:VALUE\:OF\:\angle 1\:IS\:90\degree }

\large\underline\bold{THE\:VALUE\:OF\:\angle ICD \:IS\:80\degree}

______________

\red{\text{NOTE:- PLEASE REFER THE ATTACHMENT.}}

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Anonymous: ♥️♥️♥️
Answered by Anonymous
1

{\tt{\purple{\underline{\underline{\huge{Answer:}}}}}}

\large\underline\bold{GIVEN,}

\sf\dashrightarrow \angle FEG= 90\degree

\sf\dashrightarrow \angle GAB = \angle 1

\sf\dashrightarrow \angle HBC =40\degree

\sf\dashrightarrow \angle ICD= x\degree

\sf\dashrightarrow \angle JDE= 60\degree

\sf\dashrightarrow \angle  EAB = 90\degree

\large\underline\bold{TO\:FIND,}

\sf\dashrightarrow\text{ the value of angle 1 and x}

.PROPERTY,

\bf{\boxed{\bf{ \:\: SUM\:OF\:EXTERIOR\:ANGLES\:OF\: QUADRILATERAL=360\degree\:\: }}}

\large\underline\bold{SOLUTION,}

\sf\dashrightarrow \text{ first finding the value of angle 1,}

\sf\therefore\text{ by angle sum property,}

\sf\dashrightarrow \angle GAB +\angle EAB=180\degree

\sf\implies \angle 1+ 90\degree=180\degree

\sf\implies \angle 1 =180-90

\sf\implies \angle 1= 90\degree

\large{\boxed{\bf{ \star\:\:\angle 1= 90\degree \:\: \star}}}

\sf\star \:\: \text{ Now, finding the value of x,}

\sf\therefore SUM\:OF\:EXTERIOR\:ANGLES\:OF\: QUADRILATErAL=360\degree

\sf\dashrightarrow \angle FEG+ \angle GAB + \angle HBC + \angle ICD+ \angle JDE=360\degree

\sf\implies 90\degree + 90\degree + 40\degree +x +60\degree=360\degree

\sf\implies 180\degree+100\degree = 360\degree

\sf\implies 280\degree+ x=360\degree

\sf\implies  x=360-280

\sf\implies x= 80\degree

\large{\boxed{\bf{ \:\:x= 80\degree \:\: }}}

___________________________

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