Question

please answer this question with solution​

Answer 1

Step-by-step explanation:

on the above image your ans

Answer 2

AnswEr :

-8/33.

$\bf{\large{\underline{\underline{\bf{Given\::}}}}}}$

$\sf{If\:\dfrac{x^{2}-(x+1)(x+2) }{5x+1} =6.}$

$\bf{\large{\underline{\underline{\bf{To\:find\::}}}}}}$

The value of x .

$\bf{\large{\underline{\underline{\bf{Explanation\::}}}}}}$

$\Rightarrow\sf{\dfrac{x^{2}-(x+1)(x+2) }{5x+1} =6}\\\\\\\\\Rightarrow\sf{x^{2} -(x+1)(x+2)=6(5x+1)\:\:\:\:\: \underbrace{\bf{{Cross-multiplication}}}}\\\\\\\\\Rightarrow\sf{x^{2} -\big[x(x+2)+1(x+2)\big]=30x+6}\\\\\\\\\Rightarrow\sf{x^{2} - \big[x^{2} +2x+x+2\big]=30x+6}\\\\\\\\\Rightarrow\sf{x^{2} -\big[x^{2} +3x+2\big]=30x+6}\\\\\\\\\Rightarrow\sf{\cancel{{x^{2}-x^{2}}} -3x-2=30x+6}\\\\\\\\\Rightarrow\sf{-3x-2=30x+6}\\\\\\\\\Rightarrow\sf{-3x-30x=6+2}$

$\Rightarrow\sf{-33x=8}\\\\\\\\\Rightarrow\sf{\pink{x=-\dfrac{8}{33}} }$