please answer this question with solution. it's urgent
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Answer:
55 degree bz sum of interior angles of triangle =180 degree = 180-(35+90)= 55
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Given, a right angled triangle ACB with angle ACB=90° and angle ABC=35°.
Since the sum of all angles in a triangle is 180°
Let angle BAC=x
90+35+x=180
x=180-125
x=55°
Thus, angle BAC=55°.
cos(BAC) = cos(55°) = 0.8191
Thus,
AC/AB=0.8191
4/AB=0.8191
AB=4/0.8191
AB=4.883
Rounding to the nearest hundredth,
AB=4.88
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