Math, asked by 5honey, 7 months ago

please answer this question with step by step

THE DIAGONAL OF A RHOMBUS MEASURES 16CM AND 30CM. FIND THE SIDES OF THE RHOMBUS
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Answers

Answered by tanusawant16
0

Answer:

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Step-by-step explanation:

here's your answer

Given: Diagonals AC=30cm and DB=16cm.

Since the diagonals of the rhombus bisect at right angle to each other.

Therefore, OD=

2

DB

=

2

16

=8cm

and OC=

2

AC

=

2

30

=15cm

Now, In right angle triangle DOC,

(DC)

2

=(OD)

2

+(CO)

2

⇒(DC)

2

=(8)

2

+(15)

2

⇒(DC)

2

=64+225=289

⇒DC=

289

=17cm

Perimeter of the rhombus=4× side

=4×17=68cm

Thus, the perimeter of rhombus is 68 cm.

Answered by hansika5040
0

30 + 16 / 2 = 46 / 2 = 23 cm

So , diagonals are equal and there measure is 23cm

Hope this is helpful

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