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Hi ,
let the dimensions of the each rectangle
length = l cm
breadth = b cm
according to the problem given,
perimeter of the rectangle = 48 cm
2 ( l + b ) = 48
l+b = 24 cm -----( 1 )
But side of the square = length of the
rectangle = 5 × breadth of the rectangle
l = 5b ---( 2 )
put l = 5b in equation ( 1 )
5b + b = 24
6b = 24
b = 24/6
b = 4 cm
l = 5b = 5 × 4 = 20 cm
Therefore ,
side of the square = l = 20 cm
perimeter of the square = 4l
= 4 × 20
= 80 cm
option ( D ) is correct
I hope this helps you.
:)
let the dimensions of the each rectangle
length = l cm
breadth = b cm
according to the problem given,
perimeter of the rectangle = 48 cm
2 ( l + b ) = 48
l+b = 24 cm -----( 1 )
But side of the square = length of the
rectangle = 5 × breadth of the rectangle
l = 5b ---( 2 )
put l = 5b in equation ( 1 )
5b + b = 24
6b = 24
b = 24/6
b = 4 cm
l = 5b = 5 × 4 = 20 cm
Therefore ,
side of the square = l = 20 cm
perimeter of the square = 4l
= 4 × 20
= 80 cm
option ( D ) is correct
I hope this helps you.
:)
mysticd:
:)
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