Question

Please answer this question with the solution!

Answer 1

(63)

Given Equation is x + 1/x = 2  ----- (1)

We know that:

$= \ \textgreater \ ( \sqrt{x} + \frac{1}{ \sqrt{x} } )^2 = x + \frac{1}{x} + 2$

$= \ \textgreater \ ( \sqrt{x} + \frac{1}{ \sqrt{x} } )^2 = 2 + 2$

$= \ \textgreater \ ( \sqrt{x} + \frac{1}{ \sqrt{x} } ) = 4$

$= \ \textgreater \ ( \sqrt{x} + \frac{1}{ \sqrt{x} } ) = 2$



(64)

Given Equation is x + y = 1

On cubing both sides, we get

= > (x + y)^3 = (1)^3

= > x^3 + y^3 + 3xy(x + y) = 1

= > x^3 + y^3 + 3xy(1) = 1

= > x^3 + y^3 + 3xy = 1.


Hope this helps!

Answer 2

Hi,

Please see the attached file!



Thanks