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(x-a)^3 + (x-b)^3 + (x-c)^3 -3(x-a)(x-b)(x-c) when a+b+c=3x
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Step-by-step explanation:
(x-a)^3 + (x-b)^3 + (x-c)^3 -3(x-a)(x-b)(x-c)
Let x-a=p,x-b=q,x-c=r
then p+q+r=x-a+x-b+,x-c=x+x+x-(a+b+c)=3x-3x=0
so p+q+r=0
then p³+q³+r³=3pqr
or p³+q³+r³-3pqr=0
putting values of p,q,r
(x-a)^3 + (x-b)^3 + (x-c)^3 -3(x-a)(x-b)(x-c)=0
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