PLEASE ANSWER THIS QUESTION
X and Y can do a piece of work 4 and 6 days, respectively. If Y works on the first day and they work on alternate days, in how many days will twice the amount of work be completed?
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Dear Student,
Solution:
As X can do a piece of work in = 4 days
and Y can do that work in = 6 days
Now,to calculate total unit of work,take LCM of 6 and 4
LCM (4,6) = 12 unit of work
Efficiency of X per day = 1/4 unit
For whole work = 12/4 = 3 unit /day
Efficiency of Y per day = 1/6
For whole work = 12/6 = 2 unit/day
As they work alternative days
As Y starts then X = in 2 days they work = 3+2 = 5 unit
work done in 2 days = 5 unit
like that in next two days = 5 unit
in 4 days work done = 10 unit
at 5 day Y works for 2 unit of work
it completes in 2/6 = 1/3= 0.33 day
Total time = 4+0.33 = 4.33 days
Twice the work will complete in 2*4.33= 8.66 day
you can convert 0.66 in hours if required
Hope it helps you.
Solution:
As X can do a piece of work in = 4 days
and Y can do that work in = 6 days
Now,to calculate total unit of work,take LCM of 6 and 4
LCM (4,6) = 12 unit of work
Efficiency of X per day = 1/4 unit
For whole work = 12/4 = 3 unit /day
Efficiency of Y per day = 1/6
For whole work = 12/6 = 2 unit/day
As they work alternative days
As Y starts then X = in 2 days they work = 3+2 = 5 unit
work done in 2 days = 5 unit
like that in next two days = 5 unit
in 4 days work done = 10 unit
at 5 day Y works for 2 unit of work
it completes in 2/6 = 1/3= 0.33 day
Total time = 4+0.33 = 4.33 days
Twice the work will complete in 2*4.33= 8.66 day
you can convert 0.66 in hours if required
Hope it helps you.
MERCURY1234:
but the answer is 9.666
ok,i will check
if it will do like that, 12/5 = 2.4, so total work done = 2.4*2= 4.8,hence double work will be done in 4.8*2= 9.6 days
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