please answer this question13 and 14 answer
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13.
area of the trapezium =1/2× sum of the parallel sides ×distance between them
=1/2×(250+130)×80
=380×40=1520cm square
14. let the parallel sides be 7x,5x
area of the trapezium =1/2×distance them ×sum of the parallel sides
252=1/2×(7x+5x)×14
252÷14=1/2×12x
18×2=12x
36/12=x
3cm =x
7x=7(3)=21
5x=5(3)=15.
hope this helps you.....
area of the trapezium =1/2× sum of the parallel sides ×distance between them
=1/2×(250+130)×80
=380×40=1520cm square
14. let the parallel sides be 7x,5x
area of the trapezium =1/2×distance them ×sum of the parallel sides
252=1/2×(7x+5x)×14
252÷14=1/2×12x
18×2=12x
36/12=x
3cm =x
7x=7(3)=21
5x=5(3)=15.
hope this helps you.....
anushka142:
252kaha se aaraha hai
itd the area of the trapezium
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