Math, asked by sandhya3635, 5 months ago

please answer this questions 6&7​

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Answered by soni91085
0

Answer:

Q6 Answer

8182199

Q7 Answer

1080.5625

Step-by-step explanation:

Question 6 Answer

Given

The population of Hyderabad was 6809000 in the year 2011.

it was increases by 4.7 % annum.

we need to calculate the population of after 4 years with given rate of interest.

we will use the compounding formula

Z=A+(1 +r/100) t

where Z is population at the end of duration

A is present population

t is tme perior

r is rate of interest

we we know that 4.7 % = 0.047

putting the values

Z=6809000+(1+4.7/100)⁴

Z =6809000 (1.047) ⁴

Z=6809000 ×1.2016741717

Z =8182199

does does population at the end of 2015 will be 8182199......

Question 7 Answer

For 1st year

P=10000, R = 8.7, T=1

interest= PRT /100

=(10,000×8.7 ×1 )/100

=850

amount = interest+principal = 10000 +850

= ₹10850

for for second year principal will be amount of previous year ( since interest is compound) .

P= 10850, R = 8.5%, T = 3 months = 3/12 years = 0.25 years

interest = PRT/100

=(10850 ×8.5%×0.25 )/100

₹230.5625

total interest= 850 + 230.5625 =₹1080.5625

★ compound interest paid after 1 year and 3 months is ₹1080.5625 .........

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