Math, asked by owphen50, 5 months ago

please answer this questions for me please q.no.7 please and no spam please​

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Answers

Answered by kartik2507
0

Step-by-step explanation:

b)

 {8}^{ -  \frac{1}{3} }  \times  {8}^{ -  \frac{1}{3} } ( {8}^{ \frac{1}{3} }  -  {8}^{ \frac{2}{3} } ) \\ =   {( {(2)}^{3} )}^{ -  \frac{1}{3} }  \times ( { {(2)}^{3}) }^{ -  \frac{1}{3} } ( {( {2)}^{3}) }^{ \frac{1}{3} }  - ( {( {2)}^{3}) }^{ \frac{2}{3} } ) \\  =  {2}^{ -  \frac{3}{3} }  \times  {2}^{ -  \frac{3}{3} } ( {2}^{ \frac{3}{3} }  -  {2}^{ \frac{6}{3} } ) \\  =  {2}^{ - 1}  \times  {2}^{ - 1} (2 -  {2}^{2} ) \\  =  \frac{1}{2}  \times  \frac{1}{2} (2 - 4) \\  =  \frac{1}{2}  \times  \frac{1}{2}  \times  - 2 \\  =  -  \frac{1}{2}  \\ or \\  =  { - 2}^{ - 1}

Hope you get your answer

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