Math, asked by choudharyhardik520, 3 days ago

please answer this
questions is in the picture

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Answered by meenukaushik

0

Answer:

given BD=CD

BD+CD=BC

AD IS COMMON

PROOF:-

TAKE TRIANGLE ABD

WE KNOW THAT SUM OF 2SIDE OF TRIANGLE IS GREATER THE OTHER SIDE

THEREFORE

AB+AB>AD (eq 1)

TAKE OTHER TRIANGLE ACD

AC+CD>AD (eq 2)

add eq 1 and 2

AB+BC+CD>2AD (Since BD+CD=BC)

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