Math, asked by pjbhatiya02, 19 hours ago

Please answer this questions mate​

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Answers

Answered by bikshampuram1988
2

Step-by-step explanation:

⟹ \frac{2 +  \sqrt{3} }{ {2}^{2}  -  \sqrt{3 {}^{2} } }  +  \frac{3}{3 -  \frac{}{} \sqrt{5}  }  \\  ⟹\frac{2 +  \sqrt{3} }{ 4  -  \sqrt{3 {}^{2} } }   + \frac{3}{3 -  \frac{}{} \sqrt{5}  }  \\ \green{⟹using \:  \sqrt{ {x}^{2} }  = x} \\  ⟹ \frac{2 +  \sqrt{3} }{4 - 3}  =  \frac{3}{3 -  \sqrt{5} }  \\ ⟹ \frac{2 +  \sqrt{3} }{1}  =  \frac{3}{3 -  \sqrt{5} }  \\ ⟹2 +  \sqrt{3}  =  \frac{3}{3 -  \sqrt{5} }  \\ ⟹2 +  \sqrt{3}  +  \frac{3}{3 -  \sqrt{5} }  \\ ⟹2 +  \frac{}{}  \sqrt{3}  +  \frac{9 + 3 \sqrt{5} }{ {3}^{2}  -  \sqrt{ {5}^{2} } }  \\  ⟹2 +  \sqrt{3}  +  \frac{3(3 +  \sqrt{5}) }{ {3}^{2}  -  \sqrt{ {5}^{2} } }  \\ ⟹2 +  \sqrt{3}  +  \frac{3(3 +  \sqrt{5}) }{ 9-   5}  \\ \rule{200pt}{2pt} \\ \red{thus ⟹2 +  \sqrt{3}  +  \frac{3(3 +  \sqrt{5} )}{4}is \: the \: answer..} \:

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