Question

please answer this quewtion​

Answer 1

We have, x = tanA + sinA

y = tanA − sinA

now, x + y = 2 tanA

x − y = 2 sinA

now, LHS = (x+y/x−y)^2 − (x+y/2)^2

=(2 tanA/2 sinA)^2 − (2 tanA/2)^2

=(sinA /cosA × 1/sin A) − tan^2A

=sec^2A − tan^2A=1=RHS