Question

Please answer this quick
If the area of an isosceles triangle is 120cm^ and the length of its equal sides is 17cm find the base.

Answer 1

1/2*b*h =120
BH=240
h=
$\sqrt{( {17}^{2} - \frac{ {b}^{2} }{4} ) }$
$57600 = {b}^{2} (289 - \frac{ {b}^{2} }{4} )$
b= 30, -30, 16, -16
b = 30 or 16