Question

please answer this quickly

Answer 1

Hey there

$x = 2 - \sqrt{3}$

And we have to find

${x}^{2} + 1 \div {x}^{2}$

${x}^{2} = (2 - \sqrt{3} ) {}^{2}$

So

$(a - b) {}^{2} = {a}^{2} - 2ab + {b}^{2}$

So

It will be

2^2-2 *2root 3-3

So it will be

$4 - 4 \sqrt{3} - 3$now we know x square

Then

1/x^2 will be

1/1-4 root 3 * 1+ 4 root 3/ 1+ 4 root 3

Solve it and the value you will get will be added to

1-4 root 3