Question

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Answer 1

Answer:-

Let the force exerted be x.

According to Pascal's law, the pressure exerted anywhere in a confined liquid is transmitter equally and undiminished in all directions throughout the liquid.

So,

$\boxed{\sf \frac{F_{1}}{A_{1}}= \frac{F_{2}}{A_{2}}}$

$\sf \implies \frac{2500}{1250} = \frac{x}{25}$

$\sf \implies2 = \frac{x}{25}$

$\sf \implies x= 25 \times 2$

$\sf \implies x= 50N$

Hence, the force exerted on the smaller piston is 50N.