Question

please answer this sm1 fast.... advance tq to whoever ans this

Answer 1

let us calculate net resistance first

r1 and r2 in series

r12= 6+4 = 10 ohms

r3 and comb of r1 and r2 in parallel

hence net resistance

1/r(net)=1/10+1/10

r(net)= 5 ohms

H=I^2RT

T=1 sec

H=I^2R

I^2=H/R

i^2=10/10 = 1 ampere

I= 1A

current in 10 ohm resistor is 1 ampere

voltage in 10 ohm resistor

V=IR

V=1*10= 10 V

since R1 and R2 are in parallel with R3 same voltage will be there across them also

between R1 and R2 voltage will divide equally that is 5V

current in 4 ohm resistor= I =V/R

I=5/4 A

heat produced per sec H= I^2R

H= (5/4)^2*4

H=25/4

H=6.2 J

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