Question

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Answer 1

Answer:

2 + ✓3 are two Zeroes of the given p ( x ) .

[ x - ( 2 + √ 3 ) ] [ x - ( 2 - √ 3 ) ]

[ x - 2 + √ 3 ] [ x - 2 - √ 3 ]

= x ²- 4 x + 1 = 0 = = factor of

p ( x ) = x ⁴ - 6 x³ - 26 x² + 138 x - 35 .

Now ,

We divide the p ( x ) by x ² - 41 + 1 .

Refer image ,

x² - 2 x - 35

= x² - 7 x + 5 x - 35

= x ( x - 7 ) + 5 ( x - 7 )

x = -5 and x = 7 .

Zeroes of the p ( x ) are ( 2 + √ 3 ) , 2 - √ 3 , -5 and 7 .