Question

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Answer 1

Answer:

Given, a. H2CO3

here in this compound there are 2 H, 1 C and 3 O

So, molecular weight can be calculated as:

H2CO3 = 2×1 + 1×12 + 3×16

= 2+12+48 = 62g/mol

Similarly we can also calculate the molecular weight of compound CaSO4

=> CaSO4 = 1×40 + 1×32 + 4×16

= 40+32+64 = 132g/mol