Question

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Answer 1

Let the digit in ten's place be x.

Then, the digit in the hundred's place =3/x

and digit in the unit's place = 4×x/3

= 4x/3

∴ The original number = 100× x/3 +10×x+4x/3

=100x/3 +10x+ 4x/3

=100x+30x+4x/3

= 134x/3

In the new number,

Digit in the ten's place =

4x/3

Digit in the unit's place =x

Digit in the hundred's place =

X/3

100× 3x +10× 4x/3 +x=

100x+40x+3x

=

143x/3

Given,

143x/3 − 134x/3

=18

⇒

9x/3

=18

⇒x=6

∴ Original number =

134/3 ×6=268

∴25% of 268=

100/25

×268=

268/4

=67

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Answer 2

Answer:

24 is the correct answer