Question

please answer this sum​

Answer 1

if x= 6+√35

1/x= 1/6+√35
after rationalising
=6-√38
x+1/x=(6+√35)+(6-√35)

Answer 2

Heymate!

Here's the solution...⬇⬇

$x = 6 + \sqrt{35 } \\ \frac{1}{x} = \frac{1}{6 + \sqrt{35} } \\ = \frac{6 - \sqrt{35} }{(6 + \sqrt{35} )(6 - \sqrt{35} )} \\ = \frac{6 - \sqrt{35} }{ {6}^{2} - { \sqrt{35} }^{2} } \\ = \frac{6 - \sqrt{35} }{36 - 35} \\ = 6 - \sqrt{35}$

Thus,
$x + \frac{1}{x} = 6 + \sqrt{35} + 6 - \sqrt{35} \\= 6 + 6 = 12$

Therefore,

$x + \frac{1}{x} = 12$

I hope it helps you...