please answer this. THE sum of ages of two of two friends is 20years. Four years ago, the product of their ages in years was 48. find their present age
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age of 2 frnds be x,y
A.T.Q.
x+y=20
y=20-x
(x-4)(y-4)=48
(x-4)(20-x-4)=48
(x-4)(16-x)=48
16x-64-x²+4x=48
-x²+20x-112=0
x²-20x+112=0
then solve the equation
A.T.Q.
x+y=20
y=20-x
(x-4)(y-4)=48
(x-4)(20-x-4)=48
(x-4)(16-x)=48
16x-64-x²+4x=48
-x²+20x-112=0
x²-20x+112=0
then solve the equation
tripti28:
plz mark as BRAINLIEST
thx when the option will be appear I will
ok....thnx for dat
np just keep the good work up
ohk.. !!
sorry there is no option
ya...the option will come only
when anyone else will also answer thos question
kk
hm
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