Question

please answer this this is easy question only please answer this

Answer 1

I think the answer should be √x.....

Answer 2

$\sf \:given \: { \sqrt[3]{{x }^{2} } }^{ \frac{3}{4} } \\ \\ \large = \sf {x}^{2 \times \frac{1}{ \cancel3} \times \frac{ { \cancel3} }{4} } \\ \\ \sf \large= {x}^{ \cancel2 \times \frac{1}{{ \cancel4 }^{2} } } \\ \\ \large \sf = {x}^{ \frac{1}{2} }$

some laws of exponents are used here which are :-

$\sf \sqrt[b]{a} = {a}^{ \frac{1}{b} }$