Please answer this...This is very urgent....
Answers
Given : Vectors 2i + 2j + 4k , 3i + j + 2k
To find : Sinθ where θ is angle between vectors
Solution:
2i + 2j + 4k
3i + j + 2k
Sinθ = | A × B | / | A | | B|
A × B = = i(4 - 4) -j(4 - 12) + k (2 - 6) = 8j - 4k
| A × B | = √0² + 8² + 4² = √80
| A | = √2² + 2² + 4² = √24
|B | = √3² + 1² + 2² = √14
Sinθ = √80 / √24√14
=> Sinθ = √80 / √336
=> Sinθ = √5 / √21
or Cosθ = ( 2 * 3 + 2 * 1 + 4 * 2)/ | A | | B|
= 16/ √336
= 4/√21
Cos²θ = 16/21
=> 1 - Cos²θ = 1 - 16/21
=> Sin²θ = 5/21
=> Sinθ = √5 / √21
none of the given option matches
Seems mistake in data
Learn more:
two vectors 2p and p are inclined to each other at a certain angle. If the
https://brainly.in/question/11623169
If theta is the angle between unit vectors a and b then 1-a.B/1+a.B is ...
https://brainly.in/question/12243909
²
