Question

please answer this URGENT​

Answer 1

Answer:

r/2.

Explanation:

• If two resistors of resistances r1 and r2 are joined in parallel combination, r (eq ) is given by $\frac{1}{r(eq)} = \frac{1}{r1} + \frac{1}{r2}$

• It can also be calculated directly as $\frac{r1 \times r2}{r1 + r2}$

• Now, if they are equal, let their individual value be r.Hence, equivalent resistance is r/2.

Regards

Kshitij