Question

Please answer this urgent ​

Answer 1

Answer:

x square plus 1 minus 2x minus 1

Step-by-step explanation:

use formula a minus b whole square

Answer 2

(x-1)² - 1

Identity to use : a² - b² = (a+b)(a-b)

1 = 1 × 1

Therefore,

(x-1)² - 1²

[(x-1)-1][(x-1)+1]

(x-1-1)(x-1+1)

(x-2)(x)

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Some more forumulas :

(a+b)² = a² + 2ab + b²

(a-b)² = a² - 2ab + b²

(x+a)(x+b) = x² + x(a+b) + ab

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Alternative method :

Using (a-b)² = a² - 2ab + b² identity,

(x-1)² - 1

[(x)² - 2(x)(1) + 1²] - 1

[x² - 2x + 1] - 1

x² - 2x + 1 - 1

=≥ x² - 2x

taking x as common,

(x)(x-2)