Please answer this very urgent
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pritampaliitian:
The answer is x.
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Answered by
0
Let m = √x√x√x√x.......
Then m = √(x+m)
or m² = x+m
or m²-m-x=0
m= {-(-1)±√[(-1)²-(4x1x(-x))}/2
=(1±√1+4x)/2
=(1+√1+4x)/2 as x>0, only positive value can be taken
Answered by
1
let that be m=√x√x√x√x√x.....
my sq.on both side
m2=x√x√x......
so,
m2=mx
so it become
x
my sq.on both side
m2=x√x√x......
so,
m2=mx
so it become
x
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