Question

please.answer this with correct explanation​

Answer 1

pH = 3.602

pH = -log[H⁺] ions

3.602 = log [$\frac{1}{H^+}$]

$10^3^.^6^0^2$ = $\frac{1}{[H^+]}$

[H⁺] = $\frac{1}{10^3^.^6^0^2}$

[H⁺] = $\frac{1}{4000}$ (approx)

[H⁺] = 2.5 x 10⁻⁴

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Answer 2

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