Math, asked by sneha0005, 8 months ago

please answer this with explaination ​

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Answers

Answered by stutikharbanda03
2

Answer:

x= 14 sahils age and mothers age = 42

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Answered by Uriyella
4
  • Present age of Sahil = 14 years.
  • Present age of Sahil's mother = 42 years.

Given :–

  • The present age of Sahil's mother is three times of the Sahil's age.
  • After 5 years, sum of their ages = 66 years.

To Find :–

  • Present age of their ages (Sahil and his mother).

Solution :–

Let,

The age of Sahil be x.

The age of his mother be 3x because his mother is three times of the Sahil's age. [Given]

According to the given condition,

After 5 years,

• The age of Sahil = x + 5.

• The age of his mother = 3x + 5.

Sum of their ages is 66.

So,

→ (x + 5) + (3x + 5) = 66 ––––(1)

Now, we need to find the value of x.

So,

→ x + 5 + 3x + 5 = 66

→ x + 3x + 5 + 5 = 66

→ 4x + 10 = 66

→ 4x = 66 – 10

→ 4x = 56

→ x =  \sf \cancel{\dfrac{56}{4}}

→ x = 14

Now, we have to find their ages.

Sahil's age = x = 14 years.

His mother's age = 3x = 3 × 14 = 42 years.

Hence,

The present age of Sahil = 14 years.

The present age of Sahil's mother = 42 years.

Verification :–

Substitute their ages in equation (1),

→ (x + 5) + (3x + 5) = 66

  • x = 14.
  • 3x = 42.

→ 14 + 5 + 42 + 5 = 66

→ 19 + 47 = 66

→ 66 = 66

Hence Verified !!

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