Question

please answer this with written in copy and step by step​

Answer 1

1.SOLUTION :-

H20 molecular weight=18u.

H20 GM. WEIGHT=36.0gm (given).

.°. number of moles =H20 GM. WEIGHT/H20 molecular weight

.°. number of moles = 36.0/18

.°. number of moles in H2O= 0.2moles

.°. 1 AVAGADRO NUMBER=6.022×10^23

.°.number of gram molecule in h20=number of moles in H2O ×AVAGADRO NUMBER.

.°. number of gram molecule in h20=0.2×6.022×10^23.

.°.number of gram molecule in h20= 12.044×10^22 molecules.

2. solution:-

H2so4molecular weight=98u.

H2so4 GM. WEIGHT=0.98gm (given).

.°. number of moles =H20 GM. WEIGHT/H20 molecular weight

.°. number of moles = 0.98/98

.°. number of moles in h2so4= 0.1moles

.°. 1 AVAGADRO NUMBER=6.022×10^23

.°.number of gram molecule in h20=number of moles in H2so4 ×AVAGADRO NUMBER.

.°. number of gram molecule in h2so4=0.1×6.022×10^23.

.°.number of gram molecule in h2so4= 0.622×10^22 molecules.

3. solution:-

Hcl molecular weight=35.5u.

Hcl GM. WEIGHT=3.65gm (given).

.°. number of moles =Hcl GM. WEIGHT/Hcl molecular weight

.°. number of moles = 3.65/35.5

.°. number of moles in Hcl= 0.10moles

.°. 1 AVAGADRO NUMBER=6.022×10^23

.°.number of gram molecule in h20=number of moles in H2O ×AVAGADRO NUMBER.

.°. number of gram molecule in hcl=0.10×6.022×10^23.

.°.number of gram molecule in hcl = 0.622×10^22 molecules.

4.Solution:-

ca(oh)2 molecular weight=74u.

ca(oh)2 GM. WEIGHT=10gm (given).

gm (given). .°. number of moles =ca(oh)2 GM. WEIGHT/ca(oh)2 molecular weight

molecular weight.°. number of moles = 10/74

.°. number of moles in ca(oh)2= 0.1moles

moles.°. 1 AVAGADRO NUMBER=6.022×10^23

moles.°. 1 AVAGADRO NUMBER=6.022×10^23.°.number of gram molecule in ca(oh)2 =number of moles in ca(oh)2 ×AVAGADRO NUMBER.

×AVAGADRO NUMBER.

.°. number of gram molecule in ca(oh)2 =0.1×6.022×10^23.

.°.number of gram molecule in ca(oh)2 = 0.622×10^22 molecules.