Question

Please answer this: x2 + 2x – 48

Answer 1

x^2+2x-48 =0

now factorise this

a=1, b=2 ,c= -48

(-48= -8×6 and 8-6=2=b)

x^2-8x+6x-48=0

x(x-8)+6(x-8)=0

(x-8) (x+6)=0

x-8=0 or x+6=0

x=8 or x= -6

Answer 2

Answer:

Mark me as a Brainlist plz. Becoz ur one Brainlist makes me genious rank.

Step-by-step explanation:

Given :-

x²+2x-48=0

Solving :-

x²+2x-48=0

=> x²-6x+8x-48=0

=>x(x-6) + 8(x-6)=0

=> (x+8) (x-6) =0

either

x +8 = 0 (or) x - 6 =0

then

x = - 8 (or) x = 6

=> x = -8 ,6

so the zeroes of the polynomial x²+2x-48=0 is -8 or 6