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a² + 2b = 7 ;
b² + 4c = -7 ;
c² + 6a = - 14 ;
a² + b² + c² + 2b + 4c + 6a + 14 = 0 (-7+7=0)
(a² + 6a + 9) + (b² + 2b + 1) + (c² + 4c + 4) = 0
( a + 3)² + (b + 1)² + (c + 2)² = 0
a + 3 = 0 b + 1 = 0 c + 2 = 0
a = -3 b = -1 c = -2
so a² + b² + c² = 9 + 1 + 4 = 14
aditya7181:
answer shold be from options given below question
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