please answer those questions below
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The solution is written is your book.Don't act like a fool
shakthikaruna:
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Hey dear,
••|Vector A|=50,@=45°
Ax=Acos 45°=50/√2=25√2 i
Ay=A sin 45°=50/√2=25√2 j
••|Vector B|=50,@=135,
Bx=Bcos 135=-50/√2=-25√2 i
By=B sin 135°=50/√2=25√2 j,
••|Vector C|=50,@=315
Cx=C cos 315°=50/√2=25√2 I,
Cy=C sin 31&°=-C sin45°=-25√2j
Rx=Ax+Bx+Cx=25√2i
,Ry=Ay+By+Cy=25√2j
••|Vector R|=√(Rx^2+Ry^2)=50
Tan ®=Ry/Rx=1=tan45°
Hence,the resultant is Vector R=50, angle ®=45°.
Hope it helps,.
Mark this as brainliest
••|Vector A|=50,@=45°
Ax=Acos 45°=50/√2=25√2 i
Ay=A sin 45°=50/√2=25√2 j
••|Vector B|=50,@=135,
Bx=Bcos 135=-50/√2=-25√2 i
By=B sin 135°=50/√2=25√2 j,
••|Vector C|=50,@=315
Cx=C cos 315°=50/√2=25√2 I,
Cy=C sin 31&°=-C sin45°=-25√2j
Rx=Ax+Bx+Cx=25√2i
,Ry=Ay+By+Cy=25√2j
••|Vector R|=√(Rx^2+Ry^2)=50
Tan ®=Ry/Rx=1=tan45°
Hence,the resultant is Vector R=50, angle ®=45°.
Hope it helps,.
Mark this as brainliest
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