Question

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Answer 1

Answer:

5) let the consecutive numbers be-

X and (x+1)

ATQ,

(X+(X+1))-13

=2X+1-13

=2X-12

6) 6X-10=2

=6X=12

=X=2

Answer 2

Answer:

5) x+x+1-13

=2x-12

6) 6x-10=2

putting the value x=2

6×2-10

12-10

2

as LHS=RHS

therefore 2 is the root of the equation

Step-by-step explanation:

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