Question

please answer to all this ​

Answer 1

Step-by-step explanation:

${2}^{x} + {2}^{x} = 192$

${2}^{x} (1 + 1) = 192$

${2}^{x} = \frac{192}{2} = 96$

$x = log_{2}(96)$

$(ii)$

${8}^{255} = {32}^{x}$

${( {2}^{3} )}^{255} = {( {2}^{5}) }^{x}$

${2}^{765} = {2}^{3x}$

$3x = 765$

$x = \frac{765}{3} = 255$

$x = 255$

$(iii)$

${2}^{2x + 2} = {4}^{2x - 1}$

$= { ({2}^{2}) }^{2x - 1}$

$= {2}^{4x - 2}$

$= > 2x + 2 = 4x - 2$

$= > 2x = 4$

$= > x = 2$