Math, asked by jeremiahpatchala, 1 year ago

Please answer to my question

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Answers

Answered by richapariya121pe22ey
1

Answer:

 \tan( \alpha )  =  \frac{5}{6}  \\  \tan( \beta )  =  \frac{1}{11}  \\  \\  \tan( \alpha  +  \beta )  =  \frac{ \tan( \alpha )  +  \tan( \beta ) }{1 -  \tan( \alpha )  \tan( \beta ) }  \\  =  >  \tan( \alpha  +  \beta )  =  \frac{ \frac{5}{6}  +  \frac{1}{11}  }{1 - ( \frac{5}{6}  \times  \frac{1}{11} )}  \\  =  >  \tan( \alpha  +  \beta )  =  \frac{ \frac{(5 \times 11) + (6 \times 1)}{6 \times 11} }{1 -  \frac{5}{66} }  \\  =  >  \tan( \alpha  +  \beta )  =  \frac{ \frac{55 + 6}{66} }{ \frac{66 - 5}{66} }  \\  =  >  \tan( \alpha  +  \beta )  =  \frac{ \frac{61}{66} }{ \frac{61}{66} }  \\  =  >  \tan( \alpha  +  \beta )  = 1 \\  =  >  \alpha  +  \beta  =  \tan^{ - 1} (1)  \\  =  >  \alpha  +  \beta =  \frac{\pi}{4}


jeremiahpatchala: Tnx 4 u
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