Math, asked by HarshBansal, 1 year ago

please answer to the 17th and 12th question in the photo

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Answered by Swaroop111
1
1+sinA.sinA = 3sinA.cosA divide by sinA.cosA 
(sin^2 A + cos^2 A) / (sinA.cosA ) + tan A = 3 
sin^2 A / (sinA.cosA ) + cos^2 A / (sinA.cosA ) + tan A = 3 
tan A + 1/tan A + tan A = 3 
2tan^2 A - 3tan A +1 = 0 
(2tan A -1)(tan A -1) = 0 
then 
tan A = 1 or tan A = 1/2

Hope it helps.
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