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MrThakur14Dec2002:
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Answer:
(a.) The standard cell may be represented by ---
Cr (s) | Cr^3+ (aq) || Cd^2+ (aq) | Cd (s).
Therefore ,
E°cell = E°right - E°left
E°cell = -0.40 -(-0.74) = + 0.34 V.
(b.) The standard cell may be represented as :-
Fe^2+ (aq) | Fe^3+ (aq) || Ag+ ( aq) | Ag (s)
Therefore ,
E°cell = E°right - E°left
E°cell = 0.80 - 0.77 = + 0.03 V
Now
delta G for a part
= - n × F × E°
where n= 6 , F = 96500 E° = .34 V
and
delta G for B part
= -n × F × E°.
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