please answer to the question please its urgent
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Hey
Step-by-step explanation:
Hope it helps you
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Hope it helps... :)
Step-by-step explanation:
Let the factor be 'y'
(5/7)^-2 x y = (15/28)^-1
(7/5)^2 x y = (28/15)^1 Because, a^-m = (1/a)^m
7^2/5^2 x y = 28/15
49x/25 = 28/15
x = 28/15 x 25/49
x = 20/21
Hence, (5/7)^-2 should be multiplied by 20/21 to get (15/28)^-1
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