Question

please answer to this question

Answer 1

computing
${3}^{6}$
3×3×3×3×3×3
=9×3×3×3×3
=27×3×3×3
=81×3×3
=243×3
${3}^{6} = 729$
3^2 =3×3=9
(3^2)^3 = 9×9×9
=81×9
=729

therefore 3^6 = (3^2)^3
hence proved

Answer 2

${3}^{6} = 3 \times 3 \times 3 \times 3 \times 3 \times 3 = 729 \\ and \: cube \: of \: {3}^{2} \\ {({3}^{2} )}^{3} = {9}^{3} = 9 \times 9 \times 9 = 729 \\ hence \: \\ {3}^{6} = {({3}^{2} )}^{3} \\ verified$