Question

please answer to this question ​

Answer 1

Let the distance covered by the peacock be AC = x m Hence the distance covered by the snake is DC = x m In right ΔABC, by Pythagoras theorem we have AC2 = AB2 + BC2 x2 = 92 + (27 – x)2 ⇒ x2 = 81 + 729 – 54x + x2 ⇒ 54x = 810 ∴ x = 15

Answer 2

Answer:

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